1884 United States presidential election in New York

The 1884 United States presidential election in New York took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. Voters chose 36 electors to the Electoral College, which selected the president and vice president.

1884 United States presidential election in New York

November 4, 1884
Turnout	87.5%[1] 1.8 pp
Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 36 0 Popular vote 563,154 562,005 Percentage 48.25% 48.15%
County Results Cleveland   40-50%   50-60%   60-70% Blaine   40-50%   50-60%   60-70%
President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

New York was won by the Democratic nominees, Governor Grover Cleveland of New York and his running mate former Senator and Governor Thomas A. Hendricks of Indiana. Cleveland and Hendricks defeated the Republican nominees, former Secretary of State and Senator James G. Blaine of Maine and his running mate Senator John A. Logan of Illinois.

Cleveland narrowly carried New York State with a plurality of 48.25% of the vote to Blaine's 48.15%, a victory margin of 0.10%. In a distant third came the Prohibition Party candidate John St. John with 2.14%, while Greenback Party candidate Benjamin Butler came in fourth, with 1.46%.

New York weighed in for this election as less than 1% more Republican than the national average.

Cleveland's narrow victory in his home state, with its 36 electoral votes, proved decisive in clinching him the 1884 election and allowing him to win the presidency. He won despite strong opposition to Cleveland from the corrupt Tammany Hall machine, which held significant influence over New York's politics.

Cleveland performed most strongly downstate in the New York City area, where he won New York County, Kings County, Queens County, and received over 60% of the vote in Richmond County. Cleveland also won nearby Suffolk County, Westchester County, and Rockland County. Blaine won much of upstate New York, including a victory in Erie County, home to the city of Buffalo, although Cleveland did manage to win Albany County, home to the state capital of Albany, along with several rural upstate counties.

Results

1884 United States presidential election in New York[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Grover Cleveland	563,154	48.25%	36
	Republican	James G. Blaine	562,005	48.15%	0
	Prohibition	John St. John	25,006	2.14%	0
	Greenback	Benjamin Butler	17,004	1.46%	0
Totals			1,167,169	100.0%	36

See also

• United States presidential elections in New York
• Grover Cleveland's first term as President of the United States

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1884 Presidential Election Results - New York". Dave Leip's U.S. Election Atlas. Retrieved 2013-10-08.