1852 United States presidential election in New York

The 1852 United States presidential election in New York took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 35 representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in New York

November 2, 1852
Turnout	84.7%[1] 5.1 pp
Nominee Franklin Pierce Winfield Scott Party Democratic Whig Home state New Hampshire New Jersey Running mate William R. King William Alexander Graham Electoral vote 35 0 Popular vote 262,083 234,882 Percentage 50.18% 44.97%
President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

New York voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 5.21%.

Results

1852 United States presidential election in New York[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Franklin Pierce of New Hampshire	William Rufus DeVane King of Alabama	262,083	50.18%	35	100.00%
	Whig	Winfield Scott of New Jersey	William Alexander Graham of North Carolina	234,882	44.97%	0	0.00%
	Free Soil	John Parker Hale of New Hampshire	George Washington Julian of Indiana	25,329	4.85%	0	0.00%
Total				522,294	100.00%	35	100.00%

See also

• United States presidential elections in New York

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1852 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved 24 December 2013.