1824 United States presidential election in New York

The 1824 United States presidential election in New York took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. The state legislature chose 36 representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in New York

October 26 – December 2, 1824

Nominee John Quincy Adams William H. Crawford Party Democratic-Republican Democratic-Republican Home state Massachusetts Georgia Running mate John C. Calhoun Nathaniel Macon Electoral vote 26 5   Nominee Henry Clay Andrew Jackson Party Democratic-Republican Democratic-Republican Home state Kentucky Tennessee Running mate Nathan Sanford John C. Calhoun Electoral vote 4 1

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and 4 different candidates from this party sought the Presidency. New York cast 26 electoral votes for John Quincy Adams, 5 for William H. Crawford, 4 for Henry Clay and 1 for Andrew Jackson.

Results

1824 United States presidential election in New York[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	John Quincy Adams			26
	Democratic-Republican	William H. Crawford			5
	Democratic-Republican	Henry Clay			4
	Democratic-Republican	Andrew Jackson			1
Totals					36

See also

• United States presidential elections in New York

References

1. "Electoral Votes for President and Vice President 1821-1837". National Archives and Records Administration. Retrieved 28 February 2013.