1884 United States presidential election in South Carolina

The 1884 United States presidential election in South Carolina took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.

United States presidential election in South Carolina, 1884

November 4, 1884

Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 9 0 Popular vote 69,845 21,730 Percentage 75.25% 23.41%

County Results Cleveland   50-60%   60-70%   70-80%   80-90%   90-100% Blaine   60-70%   70-80%   90-100%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

South Carolina voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a wide margin of 51.84%.

Results

United States presidential election in South Carolina, 1884[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	69,845	75.25%	9	100.00%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	21,730	23.41%	0	0.00%
	N/A	Others	Others	1,237	1.33%	0	0.00%
Total				92,812	100.00%	9	100.00%

References

1. "1884 Presidential General Election Results - South Carolina". U.S. Election Atlas. Retrieved 23 December 2013.