1868 United States presidential election in New York

The 1868 United States presidential election in New York took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 33 representatives, or electors to the Electoral College, who voted for president and vice president.

1868 United States presidential election in New York

November 3, 1868
Turnout	91.7%[1] 2.4 pp
Nominee Horatio Seymour Ulysses S. Grant Party Democratic Republican Home state New York Illinois Running mate Francis Preston Blair, Jr. Schuyler Colfax Electoral vote 33 0 Popular vote 429,883 419,888 Percentage 50.59% 49.41%
President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

New York voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won his home state by a very narrow margin of 1.18%, making him the first Democratic candidate since Franklin Pierce in 1852 to win the state. Seymour also became the first losing Democratic presidential candidate to win New York.

Results

1868 United States presidential election in New York[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Horatio Seymour of New York	Francis Preston Blair, Jr. of Missouri	429,883	50.59%	33	100.00%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	419,888	49.41%	0	0.00%
Total				849,771	100.00%	33	100.00%

See also

• United States presidential elections in New York

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1868 Presidential General Election Results - New York".