1884 United States presidential election in Wisconsin

The 1884 United States presidential election in Wisconsin was held on November 4, 1884 as part of the 1884 United States presidential election. State voters chose eleven electors to the Electoral College, who voted for president and vice president.

1884 United States presidential election in Wisconsin

November 4, 1884

Nominee James G. Blaine Grover Cleveland Party Republican Democratic Home state Maine New York Running mate John A. Logan Thomas A. Hendricks Electoral vote 11 0 Popular vote 161,135 146,453 Percentage 50.38% 45.79%

County Results Blaine   40-50%   50-60%   60-70%   70-80%   90-100% Cleveland   40-50%   50-60%   60-70%   70-80%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

Republican Party candidate James G. Blaine won Wisconsin with 50.38 percent of the popular vote, winning the state's eleven electoral votes.[1]

Results

Presidential Candidate	Running Mate	Party	Electoral Vote (EV)	Popular Vote (PV)
James G. Blaine of Maine	John A. Logan	Republican	11	161,135	50.38%
Grover Cleveland	Thomas A. Hendricks	Democratic	0	146,453	45.79%
John St. John	William Daniel	Prohibition	0	7,649	2.39%
Benjamin Butler	Absolom West	Greenback	0	4,598	1.44%

References

1. "1884 Presidential General Election Results – Wisconsin". Retrieved August 18, 2016.