1868 United States presidential election in Georgia

The 1868 United States presidential election in Georgia took place on November 3, 1868, as part of the wider United States Presidential election. Voters chose 9 representatives, or electors, to the Electoral College, who voted for president and vice president.

United States presidential election in Georgia, 1868

November 3, 1868

Nominee Horatio Seymour Ulysses S. Grant Party Democratic Republican Home state New York Ohio Running mate Francis P. Blair, Jr. Schuyler Colfax Electoral vote 9 0 Popular vote 102,707 57,109 Percentage 64.27% 35.73%

President before election Andrew Johnson National Union Elected President Ulysses S. Grant Republican

Background

The first readmission of Georgia to the Union occurred in 1868.

Vote

The Seymour/Blair ticket carried the state of Georgia on election day.

With 64.27% of the popular vote, Georgia would be Seymour's fourth strongest victory in terms of percentage in the popular vote after Kentucky, Louisiana and Maryland.[1]

Results

United States presidential election in Georgia, 1868 [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Horatio Seymour	102,707	64.27%	9
	Republican	Ulysses S. Grant	57,109	35.73%	0

References

1. "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
2. Dave Leip’s U.S. Election Atlas; 1868 Presidential General Election Results – Georgia

Notes