1852 United States presidential election in Maryland

The 1852 United States presidential election in Maryland took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Maryland

November 2, 1852

Nominee Franklin Pierce Winfield Scott Party Democratic Whig Home state New Hampshire New Jersey Running mate William R. King William A. Graham Electoral vote 8 0 Popular vote 40,022 35,077 Percentage 53.28% 46.69%

President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

Maryland voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Maryland by a margin of 6.59%. This was the first presidential election in which Maryland voted Democratic.

Results

1852 United States presidential election in Maryland[1][2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Franklin Pierce of New Hampshire	William R. King of Alabama	40,022	53.28%	8	100.00%
	Whig	Winfield Scott of New Jersey	William A. Graham of North Carolina	35,077	46.69%	0	0.00%
	Free Soil	John P. Hale of New Hampshire	George W. Julian of Indiana	21	0.03%	0	0.00%
Total				75,120	100.00%	8	100.00%

See also

• United States presidential elections in Maryland

References

1. "1852 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 2 December 2017.
2. "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.