1844 United States presidential election in Georgia
The 1844 United States presidential election in Georgia took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Georgia |
---|
Georgia voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Georgia by a margin of 2.38%.
Results
United States presidential election in Georgia, 1844[1] | ||||||||
---|---|---|---|---|---|---|---|---|
Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 44,147 | 51.19% | 10 | 100.00% | ||
Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 42,100 | 48.81% | 0 | 0.00% | ||
Total | 86,247 | 100.00% | 10 | 100.00% |
References
- "1844 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 23 December 2013.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.