1892 United States presidential election in Delaware
The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.
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County Results
Cleveland 40-50% 50-60%
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Elections in Delaware |
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Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.
Results
1892 United States presidential election in Delaware[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Grover Cleveland | 18,581 | 49.90% | 3 | |
Republican | Benjamin Harrison (incumbent) | 18,077 | 48.55% | 0 | |
Prohibition | John Bidwell | 564 | 1.51% | 0 | |
Write-ins | Scattered | 13 | 0.03% | 0 | |
Totals | 37,235 | 100.00% | 3 | ||
Voter turnout | — |
References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes
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