1912 United States presidential election in Delaware

The 1912 United States presidential election in Delaware took place on November 5, 1912, as part of the 1912 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

1912 United States presidential election in Delaware

November 5, 1912

Nominee Woodrow Wilson William Howard Taft Theodore Roosevelt Party Democratic Republican Progressive Home state New Jersey Ohio New York Running mate Thomas R. Marshall Nicholas M. Butler (replacing James S. Sherman) Hiram Johnson Electoral vote 3 0 0 Popular vote 22,631 15,998 8,886 Percentage 46.48% 32.85% 18.25%

County Results Wilson   40-50%   50-60%

President before election William Howard Taft Republican Elected President Woodrow Wilson Democratic

Delaware was won by Princeton University President Woodrow Wilson (D–Virginia), running with governor of Indiana Thomas R. Marshall, with 46.48% of the popular vote, against the 27th president of the United States William Howard Taft (R–Ohio), running with Columbia University President Nicholas Murray Butler, with 32.85% of the popular vote and the 26th president of the United States Theodore Roosevelt (P–New York), running with governor of California Hiram Johnson, with 18.25% of the popular vote.[1]

Delaware was the only state where the Prohibition Party received fourth place with 1.28% of the popular vote which was ahead of the Socialist Eugene V. Debs who only received 1.14% of the vote.

Results

1912 United States presidential election in Delaware[1]

Party		Candidate	Votes	%
	Democratic	Woodrow Wilson	22,631	46.48%
	Republican	William Howard Taft	15,998	32.85%
	Progressive	Theodore Roosevelt	8,886	17.30%
	Prohibition	Stuart Hamblen	623	1.28%
	Socialist	Eugene V. Debs	556	1.14%
Total votes			48,694	100.00%

See also

• United States presidential elections in Delaware

References

1. "1912 Presidential Election Results Delaware".