1892 United States presidential election in Minnesota

The 1892 United States presidential election in Minnesota took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

1892 United States presidential election in Minnesota

November 8, 1892

Nominee Benjamin Harrison Grover Cleveland Party Republican Democratic Home state Indiana New York Running mate Whitelaw Reid Adlai Stevenson I Electoral vote 9 0 Popular vote 122,823 100,920 Percentage 45.96% 37.76%   Nominee James B. Weaver John Bidwell Party Populist Prohibition Home state Iowa California Running mate James G. Field James Cranfill Electoral vote 0 0 Popular vote 29,313 14,182 Percentage 10.97% 5.31%

County Results Harrison   30-40%   40-50%   50-60%   60-70%   70-80% Cleveland   30-40%   40-50%   50-60%   60-70% Weaver   30-40%   40-50%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

Minnesota was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York.

With 5.31% of the popular vote, Minnesota proved to be Bidwell’s best performance as well as the only state where he broke 5% of the vote.[1]

Results

1892 United States presidential election in Minnesota[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Benjamin Harrison (incumbent)	122,823	45.96%	9
	Democratic	Grover Cleveland	100,920	37.76%	0
	People's	James Weaver	29,313	10.97%	0
	Prohibition	John Bidwell	14,182	5.31%	0
Totals			267,238	100.00%	9
Voter turnout					—

References

1. "1892 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
2. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Minnesota

Notes