1892 United States presidential election in Illinois
The 1892 United States presidential election in Illinois took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.
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County Results
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Elections in Illinois |
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Illinois was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. This marked the first time a Democratic candidate won Illinois since 1856 when James Buchanan carried the state.
Results
1892 United States presidential election in Illinois[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Grover Cleveland | 426,281 | 48.79% | 24 | |
Republican | Benjamin Harrison (incumbent) | 399,288 | 45.70% | 0 | |
Prohibition | John Bidwell | 25,871 | 2.96% | 0 | |
Populist | James B. Weaver | 22,207 | 2.54% | 0 | |
Totals | 873,647 | 100.00% | 24 | ||
Voter turnout | — |
Notes
References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Illinois
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