1996 United States presidential election in Hawaii

The 1996 United States presidential election in Hawaii took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.

1996 United States presidential election in Hawaii

November 5, 1996

Nominee Bill Clinton Bob Dole Ross Perot Party Democratic Republican Reform Home state Arkansas Kansas Texas Running mate Al Gore Jack Kemp Patrick Choate Electoral vote 4 0 0 Popular vote 205,012 113,943 27,358 Percentage 56.93% 31.64% 7.60%

County Results Clinton   50–60%   60–70%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

Hawaii was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 56.93% to 31.64% by a margin of 25.29%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 7.6% of the popular vote.[1]

Results

1996 United States presidential election in Hawaii
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton (incumbent)	Al Gore	205,012	56.93%	4
	Republican	Bob Dole	Jack Kemp	113,943	31.64%	0
	Reform	Ross Perot	Patrick Choate	27,358	7.60%	0
	Green	Ralph Nader	Winona LaDuke	10,386	2.88%	0
	Libertarian	Harry Browne	Jo Jorgensen	2,493	0.69%	0
	Natural Law	Dr. John Hagelin	Dr. V. Tompkins	570	0.16%	0
	U.S. Taxpayers' Party	Howard Phillips	Herbert Titus	358	0.10%	0
Totals				360,120	100.0%	4

By county

County	Clinton	Votes	Dole	Votes	Others	Votes
Hawaii	55.6%	27,262	27.6%	13.516	16.7%	8,199
Honolulu	56.3%	143,793	33.6%	85,779	10.0%	25,684
Kalawao	73.0%	46	20.6%	13	6.3%	4
Kauai	63.5%	13,357	25.3%	5,325	11.1%	2,338
Maui	59.0%	20,600	26.7%	9,323	14.1%	4,944

References

1. Leip, David. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved 2018-06-14.