1966 United States Senate election in Montana

The 1960 United States Senate election in Montana took place on November 8, 1966. Incumbent United States Senator Lee Metcalf, who was first elected to the Senate in 1960, ran for re-election. He won the Democratic primary uncontested, and moved on to the general election, where he was opposed by Tim M. Babcock, the Republican nominee and the Governor of Montana. Though the race remained close, Metcalf was able to expand on his 1960 margin of victory, and defeated Babcock to win a second term.

1966 United States Senate election in Montana

November 8, 1966

Nominee Lee Metcalf Tim Babcock Party Democratic Republican Popular vote 138,166 121,697 Percentage 53.17% 46.83%

County results Metcalf:      50–60%      60–70%      70–80% Babcock:      50–60%      60–70%

U.S. senator before election Lee Metcalf Democratic Elected U.S. Senator Lee Metcalf Democratic

Democratic primary

Candidates

• Lee Metcalf, incumbent United States Senator

Results

Democratic Party primary results[1]

Party		Candidate	Votes	%
	Democratic	Lee Metcalf (incumbent)	73,975	100.00%
Total votes			73,975	100.00%

Republican primary

Candidates

• Tim M. Babcock, Governor of Montana

Results

Republican Primary results[1]

Party		Candidate	Votes	%
	Republican	Tim M. Babcock	54,828	100.00%
Total votes			54,828	100.00%

General election

Results

United States Senate election in Montana, 1966[2]

Party		Candidate	Votes	%	±%
	Democratic	Lee Metcalf (incumbent)	138,166	53.17%	+2.44%
	Republican	Tim M. Babcock	121,697	46.83%	-2.44%
Majority			16,469	6.34%	+4.87%
Turnout			259,863
	Democratic hold		Swing

See also

• United States Senate elections, 1966

References

1. "Report of the Official Canvass of the Vote Cast at the Primary Election Held in the State of Montana, August 16, 1966". Montana Secretary of State. Retrieved July 2, 2014.
2. "Statistics of the Congressional Election of November 8, 1966" (PDF). Clerk of the United States House of Representatives. Retrieved July 2, 2014.