1860 United States presidential election in Michigan

The 1860 United States presidential election in Michigan took place on November 6, 1860, as part of the 1860 United States presidential election. Voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

1860 United States presidential election in Michigan

November 6, 1860

Nominee Abraham Lincoln Stephen A. Douglas Party Republican Democratic Home state Illinois Illinois Running mate Hannibal Hamlin Herschel V. Johnson Electoral vote 6 0 Popular vote 88,450 64,889 Percentage 57.23% 41.99%

Results by county Lincoln   50-60%   60-70%   70-80% Douglas   50-60%   60-70%   70-80%   80-90%

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

Michigan was won by Illinois Representative Abraham Lincoln (R–Kentucky), running with Senator Hannibal Hamlin, with 57.23% of the popular vote, against Senator Stephen A. Douglas (D–Vermont), running with 41st Governor of Georgia Herschel V. Johnson, with 43.97% of the popular vote.[1]

Results

1860 United States presidential election in Michigan[1]

Party		Candidate	Votes	%
	Republican	Abraham Lincoln	88,450	57.23%
	Democratic	Stephen A. Douglas	64,889	41.99%
	Southern Democratic	John C. Breckinridge	805	0.52%
	Constitutional Union	John Bell	405	0.26%
Total votes			154,549	100%

References

1. "1860 Presidential Election Results Michigan".