1812 United States presidential election in Ohio
The 1812 United States presidential election in Ohio took place as part of the 1812 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Ohio |
---|
Ohio re-elected incumbent Democratic-Republican President James Madison over Federalist candidate DeWitt Clinton. Madison won Ohio by a margin of 38.42%.
Results
1816 United States presidential election in Ohio[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | James Madison | 7,420 | 69.21% | 8 | |
Federalist | DeWitt Clinton | 3,301 | 30.79% | 0 | |
Totals | 10,721 | 100.0% | 8 | ||
References
- Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved 2019-12-08.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.