1808 United States presidential election in Ohio

The 1808 United States presidential election in Ohio took place as part of the 1808 United States Presidential Election. Voters chose eight representatives, or electors to the Electoral College, who voted for the President and Vice-President.

1808 United States presidential election in Ohio
November 4 - December 7, 1808
 
Nominee James Madison Charles Cotesworth Pinckney
Party Democratic-Republican Federalist
Home state Virginia South Carolina
Running mate George Clinton Rufus King
Electoral vote 8 0
Popular vote 11,868 3,262
Percentage 78.44% 21.55%
President before election

Thomas Jefferson
Democratic-Republican

 Elected President

James Madison
Democratic-Republican

Main article: 1808 United States presidential election

Ohio voted for the Democratic-Republican candidate, James Madison over, the Federalist candidate, Charles Cotesworth Pinckney. Madison won Ohio's eight electoral votes by a margin of 56.89%.


Results
1808 United States presidential election in Ohio[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Madison 11,868 78.44% 3
Federalist Charles Cotesworth Pinckney 3,262 21.55% 0
Totals 15,130 100.0% 3

References
  1. "Ohio 1808 Electoral College". Tufts University. Retrieved 24 March 2020.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.