1956 United States presidential election in Rhode Island
The 1956 United States presidential election in Rhode Island took place on November 6, 1956, as part of the 1956 United States presidential election which was held throughout all contemporary 48 states. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
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County Results
Eisenhower 50-60% 60-70%
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Elections in Rhode Island |
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Rhode Island voted for the Republican nominee, incumbent President Dwight D. Eisenhower of Pennsylvania, over the Democratic nominee, former Governor Adlai Stevenson of Illinois. Eisenhower ran with incumbent Vice President Richard Nixon of California, while Stevenson's running mate was Senator Estes Kefauver of Tennessee.
Eisenhower won Rhode Island by a margin of 16.53%. This is also the most recent presidential election when Rhode Island would vote more Republican than the nation as a whole.
Results
1956 United States presidential election in Rhode Island[3] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Dwight David Eisenhower of Pennsylvania | Richard Nixon of California | 225,819 | 58.26% | 4 | 100.00% | ||
Democratic | Adlai Stevenson II of Illinois | Estes Kefauver of Tennessee | 161,790 | 41.73% | 0 | 0.00% | ||
N/A | Others | Others | 2 | 0.01% | 0 | 0.00% | ||
Total | 387,611 | 100.00% | 4 | 100.00% |
References
- Although he was born in Texas and grew up in Kansas before his military career, at the time of the 1952 election Eisenhower was president of Columbia University and was, officially, a resident of New York. During his first term as president, he moved his private residence to Gettysburg, Pennsylvania, and officially changed his residency to Pennsylvania.
- "The Presidents". David Leip. Retrieved September 27, 2017.
Eisenhower's home state for the 1956 Election was Pennsylvania
- "1956 Presidential General Election Results - Rhode Island".