1918 Rhode Island gubernatorial election

The 1918 Rhode Island gubernatorial election was held on November 5, 1918. Incumbent Republican Robert Livingston Beeckman defeated Democratic nominee Alberic A. Archambault with 53.11% of the vote.

1918 Rhode Island gubernatorial election
November 5, 1918
 
Nominee Robert Livingston Beeckman Alberic A. Archambault
Party Republican Democratic
Popular vote 42,682 36,031
Percentage 53.11% 44.84%
Governor before election

Robert Livingston Beeckman
Republican

 Elected Governor

Robert Livingston Beeckman
Republican

Elections in Rhode Island
Federal government
U.S. President
U.S. Senate
U.S. House
State government
General elections
Gubernatorial elections
State Senate elections
State House of Representatives elections
Providence
Mayoral elections

General election

Candidates

Major party candidates

  • Robert Livingston Beeckman, Republican
  • Alberic A. Archambault, Democratic

Other candidates

  • Ernest Sherwood, Socialist

Results
1918 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Robert Livingston Beeckman 42,682 53.11%
Democratic Alberic A. Archambault 36,031 44.84%
Socialist Ernest Sherwood 1,648 2.05%
Majority 6,651
Turnout
Republican hold Swing

References
  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved May 20, 2020.
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