1880 United States presidential election in Alabama

The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the 1880 United States presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

United States presidential election in Alabama, 1880

November 2, 1880
Turnout	12.03% of the total population 5.19 pp[1]
Nominee Winfield Scott Hancock James A. Garfield Party Democratic Republican Home state Pennsylvania Ohio Running mate William Hayden English Chester A. Arthur Electoral vote 10 0 Popular vote 91,130 56,350 Percentage 59.99% 37.10%
County Results Hancock   40-50%   50-60%   60-70%   70-80%   80-90%   90-100% Garfield   40-50%   50-60%   60-70%   80-90%
President before election Rutherford B. Hayes Republican Elected President James Garfield Republican

Alabama was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 37.10% of the vote.[2]

Results

United States presidential election in Alabama, 1880[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Winfield Scott Hancock of Pennsylvania	William Hayden English of Indiana	91,130	59.99%	10	100.00%
	Republican	James Garfield of Ohio	Chester A. Arthur of New York	56,350	37.10%	0	0.00%
	Greenback	James B. Weaver of Iowa	Barzillai J. Chambers of Texas	4,422	2.91%	0	0.00%
Total				151,902	100.00%	10	100.00%

References

1. "1884 Presidential Election Results Alabama Total Population Turnout".
2. "1880 Presidential Election Results Alabama".