1876 United States presidential election in New Jersey

The 1876 United States presidential election in New Jersey took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1876 United States presidential election
1876 United States presidential election in New Jersey
November 7, 1876
 
Nominee Samuel J. Tilden Rutherford B. Hayes
Party Democratic Republican
Home state New York Ohio
Running mate Thomas A. Hendricks William A. Wheeler
Electoral vote 9 0
Popular vote 115,962 103,517
Percentage 52.66% 47.01%
President before election

Ulysses S. Grant
Republican

 Elected President

Rutherford B. Hayes
Republican

Elections in New Jersey
Federal government
U.S. President
U.S. Senate
U.S. House of Representatives
State government
General elections
Gubernatorial elections
Senate elections
General Assembly elections
Newark
Mayoral elections
Jersey City
Mayoral elections
Hoboken
Mayoral elections
Atlantic City
Mayoral elections

New Jersey voted for the Democratic nominee, Samuel J. Tilden, over the Republican nominee, Rutherford B. Hayes. Tilden won the state by a narrow margin of 5.65%.

Results
1876 United States presidential election in New Jersey[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Samuel J. Tilden of New York Thomas A. Hendricks of Indiana 115,962 52.66% 9 100.00%
Republican Rutherford B. Hayes of Ohio William A. Wheeler of New York 103,517 47.01% 0 0.00%
Greenback Peter Cooper of New York Samuel Fenton Cary of Ohio 714 0.32% 0 0.00%
Total 220,193 100.00% 9 100.00%

See also

References
  1. "1876 Presidential General Election Results - New Jersey".


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