1840 United States presidential election in Mississippi

The 1840 United States presidential election in Mississippi took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

United States presidential election in Mississippi, 1840

October 30 - December 2, 1840

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 4 0 Popular vote 19,515 17,010 Percentage 53.43% 46.57%

County Results Harrison   50-60%   60-70%   70-80%   80-90% Tie   50% Van Buren   50-60%   60-70%   70-80%   80-90%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

Mississippi voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Mississippi by a margin of 6.86%. As of 2020, this is the only election in American history in which Mississippi and Alabama voted for different candidates.

Results

United States presidential election in Mississippi, 1840[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	19,515	53.43%	4	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	17,010	46.57%	0	0.00%
Total				36,525	100.00%	4	100.00%

References

1. "1840 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved 23 December 2013.