1836 United States presidential election in Tennessee
The 1836 United States presidential election in Tennessee took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Tennessee |
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Government |
Tennessee voted for Whig candidate Hugh White, a Senator for Tennessee, over Democratic candidate Martin Van Buren. White won Tennessee by a margin of 15.84%.
Results
United States presidential election in Tennessee, 1836[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Whig | Hugh White of Tennessee | John Tyler of Virginia | 36,027 | 57.92% | 15 | 100.00% | ||
Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 26,170 | 42.08% | 0 | 0.00% | ||
Total | 62,197 | 100.00% | 15 | 100.00% |
References
- "1836 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved 23 December 2013.
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