Sękowice, Lubusz Voivodeship
Sękowice [sɛnkɔˈvit͡sɛ] (German: Schenkendorf) is a village in the administrative district of Gmina Gubin, within Krosno Odrzańskie County, Lubusz Voivodeship, in western Poland, close to the German border.[1] It lies approximately 4 kilometres (2 mi) south of Gubin, 30 km (19 mi) south-west of Krosno Odrzańskie, and 55 km (34 mi) west of Zielona Góra.
Sękowice | |
|---|---|
Village | |
  Sękowice | |
| Coordinates: 51°55′N 14°43′E | |
| Country |  Poland |
| Voivodeship | Lubusz |
| County | Krosno Odrzańskie |
| Gmina | Gmina Gubin |
Before 1945 the area was part of Germany (see Territorial changes of Poland after World War II).
References
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.