Lutetium(III) hydroxide
Lutetium(III) hydroxide is an inorganic compound with the chemical formula Lu(OH)3.
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| ChemSpider | |
| ECHA InfoCard | 100.036.820  |
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| Properties | |
| Lu(OH)3 | |
| Molar mass | 225.991 |
| Appearance | white solid[1] |
| Related compounds | |
Other anions |
lutetium oxide |
Other cations |
ytterbium(III) hydroxide |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). | |
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Production
Reacting lutetium chloride and alkalis will first produce Lu(OH)2Cl, then it will become Lu(OH)2.5Cl0.5. Finally, the reaction will produce Lu(OH)3.[2]
- LuCl3+2 NaOH→Lu(OH)2Cl+2 NaCl
- Lu(OH)2Cl+0.5 NaOH→Lu(OH)2.5Cl0.5+0.5 NaCl
- Lu(OH)2.5Cl0.5+0.5 NaOH→Lu(OH)3+0.5 NaCl
Chemical properties
Lutetium(III) hydroxide can react with acid and form lutetium(III) salts：
- Lu(OH)3 + 3 H+ → Lu3+ + 3 H2O
While heating lutetium(III) hydroxide, it will produce LuO(OH), continued heating could produce Lu2O3.[1]
References
- 《无机化学丛书》. 第七卷 钪 稀土元素. 易宪武 等主编. 科学出版社. P168~171. (2)氢氧化物
- Aksel'rud, N. V.; Akhrameeva, T. I. Basic chlorides and hydroxide of lutetium. Zhurnal Neorganicheskoi Khimii, 1962. 7. pp 1998-2001. ISSN: 0044-457X.
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