Lake Santee, Indiana

Lake Santee is an unincorporated town and census-designated place in Decatur and Franklin counties, Indiana, United States. As of the 2010 census, it had a population of 820.[1]

Lake Santee, Indiana
Census-designated place
Location of Lake Santee in Decatur County and Franklin County, Indiana.
Lake Santee Location of Lake Santee in Decatur County and Franklin County, Indiana.
Coordinates: 39°24′36″N 85°18′27″W
Country	United States
State	Indiana
County	Decatur, Franklin
Township	Fugit, Salt Creek
Area
• Total	2.8 sq mi (7.3 km^2)
• Land	2.5 sq mi (6.4 km^2)
• Water	0.3 sq mi (0.9 km^2)
Elevation	1,015 ft (309 m)
Population  (2010)[1]
• Total	820
ZIP code	47240
FIPS code	18-41444[2]

History

Lake Santee was built up in the 1960s as a housing development centered on a reservoir of the same name.[3]

Geography

Lake Santee is located at 39°24′36″N 85°18′27″W in southeastern Indiana. It is situated 13 miles (21 km) northeast of Greensburg and 12 miles (19 km) northwest of Batesville.

According to the U.S. Census Bureau, the CDP has a total area of 2.8 square miles (7.3 km²), of which 2.5 square miles (6.4 km²) is land and 0.35 square miles (0.9 km²), or 12.60%, is water. The water area consists entirely of Lake Santee, the reservoir.[4]

Demographics

Historical population
Census	Pop.		%±
U.S. Decennial Census[5]

References

1. "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Lake Santee CDP, Indiana". United States Census Bureau. Retrieved October 4, 2012.
2. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
3. "History of Lake Santee". Retrieved 7 September 2014.
4. "Geographic Identifiers: 2010 Demographic Profile Data (G001): Lake Santee CDP, Indiana". United States Census Bureau. Retrieved October 4, 2012.
5. "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.