First inauguration of Grover Cleveland

The first inauguration of Grover Cleveland as the 22nd President of the United States was held on Wednesday, March 4, 1885, at the East Portico of the United States Capitol in Washington, D.C. This was the 25th inauguration and marked the commencement of the first four-year term of Grover Cleveland as President and the only term of Thomas A. Hendricks as Vice President. Hendricks died 266 days into this term, and the office remained vacant since there was no constitutional provision which allow an intra-term vice-presidential office filling; it would be regulated by the Twenty-fifth Amendment in 1967.

First presidential inauguration of Grover Cleveland
Cleveland delivering his inaugural address
DateMarch 4, 1885 (1885-03-04)
LocationUnited States Capitol,
Washington, D.C.
ParticipantsGrover Cleveland
22nd President of the United States
— Assuming office
Morrison Waite
Chief Justice of the United States
— Administering oath
Thomas A. Hendricks
21st Vice President of the United States
— Assuming office
George F. Edmunds
President pro tempore of the United States Senate
— Administering oath
1889 →

Chief Justice Morrison Waite administered the presidential oath of office, and Cleveland held a Bible given to him at age 15 by his mother as he recited it.[1] Cleveland's second inauguration took place eight years after the first, as his two terms in office were not consecutive. He is the only U.S. president to serve non-consecutive terms.[2]

See also

References
  1. "The 25th Presidential Inauguration: Grover Cleveland, March 04, 1885". United States Senate. Retrieved May 3, 2020.
  2. "The 27th Presidential Inauguration, Grover Cleveland, March 04, 1893". United States Senate. Retrieved May 3, 2020.
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