1885 Iowa gubernatorial election

The 1885 Iowa gubernatorial election was held on November 3, 1885. Republican nominee William Larrabee defeated Democratic nominee Charles E. Whiting with 50.76% of the vote.

1885 Iowa gubernatorial election
November 3, 1885
 
Nominee William Larrabee Charles E. Whiting
Party Republican Democratic
Popular vote 175,605 168,584
Percentage 50.76% 48.73%
Governor before election

Buren R. Sherman
Republican

 Elected Governor

William Larrabee
Republican

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General election

Candidates

Major party candidates

  • William Larrabee, Republican
  • Charles E. Whiting, Democratic

Other candidates

  • James Michelwait, Prohibition
  • Elias Doty, Greenback

Results
1885 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William Larrabee 175,605 50.76%
Democratic Charles E. Whiting 168,584 48.73%
Prohibition James Michelwait 1,412 0.41%
Greenback Elias Doty 314 0.09%
Majority 7,021
Turnout
Republican hold Swing

References
  1. Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 15, 2020.
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