2019 Kiskút Open – Doubles

Irina Bara and Maryna Zanevska won the title, defeating Akgul Amanmuradova and Elena Bogdan in the final, 3–6, 6–2, [10–8].

Doubles
2019 Kiskút Open
Champions Irina Bara
Maryna Zanevska
Runners-up Akgul Amanmuradova
Elena Bogdan
Final score3–6, 6–2, [10–8]

This was the first edition of the tournament.[1]

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 G García Pérez
F Stollár
3 0r
  I Bara
M Zanevska
6 1 I Bara
M Zanevska
6 6
  RL Jani
P Ormaechea
5 6 [10] RL Jani
P Ormaechea
2 3
  M Chwalińska
A Nagy
7 3 [7] I Bara
M Zanevska
77 6
3 N Dascălu
D Kovinić
w/o 3 N Dascălu
D Kovinić
63 1
  V Juhászová
M Klaffner
3 N Dascălu
D Kovinić
6 6
  A Bondár
R Šramková
0 6 [10] A Bondár
R Šramková
4 2
  G Cé
S Waltert
6 4 [8] I Bara
M Zanevska
3 6 [10]
  M Chernyshova
C Škamlová
w/o 4 A Amanmuradova
E Bogdan
6 2 [8]
WC Á Bukta
T Pereira
M Chernyshova
C Škamlová
2 64
WC B Békefi
D Drahota-Szabó
3 4 4 A Amanmuradova
E Bogdan
6 77
4 A Amanmuradova
E Bogdan
6 6 4 A Amanmuradova
E Bogdan
2 6 [10]
  M Bulgaru
IG Ghioroaie
6 6 2 A Anshba
A Dețiuc
6 4 [4]
  J Marková
D Seguel
4 2 M Bulgaru
IG Ghioroaie
2 3
  N Potočnik
N Radišič
4 3 2 A Anshba
A Dețiuc
6 6
2 A Anshba
A Dețiuc
6 6

References

  1. "W60 Székesfehérvár". www.itftennis.com.
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