2019 Berkeley Tennis Club Challenge – Doubles

Nicole Gibbs and Asia Muhammad were the defending champions, but both players chose not to participate.[1]

Doubles
2019 Berkeley Tennis Club Challenge
Champions Madison Brengle
Sachia Vickery
Runners-up Francesca Di Lorenzo
Katie Swan
Final score6–3, 7–5

Madison Brengle and Sachia Vickery won the title, defeating Francesca Di Lorenzo and Katie Swan in the final, 6–3, 7–5.

Seeds

  1. Giuliana Olmos / Luisa Stefani (Semifinals)
  2. Hsieh Yu-chieh / You Xiaodi (Quarterfinals)
  3. Han Na-lae / Hiroko Kuwata (Quarterfinals)
  4. Chen Pei-hsuan / Wu Fang-hsien (Quarterfinals)

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 G Olmos
L Stefani
6 6
  L Cabrera
Z Hives
3 4 1 G Olmos
L Stefani
6 6
  J Namigata
M Yonehara
6 6 J Namigata
M Yonehara
1 1
Alt F Al-Nabhani
D-b Kim
3 3 1 G Olmos
L Stefani
3 77 [9]
3 N-l Han
H Kuwata
6 6 F Di Lorenzo
K Swan
6 62 [11]
  H Arakawa
A Shimizu
4 4 3 N-l Han
H Kuwata
65 3
  F Di Lorenzo
K Swan
6 6 F Di Lorenzo
K Swan
77 6
  B Boren
G Brodsky
3 4 F Di Lorenzo
K Swan
3 5
  K Ahn
C Harrison
77 6 M Brengle
S Vickery
6 7
  D Khazaniuk
C Simmonds
64 4 K Ahn
C Harrison
77 6
WC M Thiel
C Van Nguyen
2 4 4 P-h Chen
F-h Wu
63 0
4 P-h Chen
F-h Wu
6 6 K Ahn
C Harrison
1 0
  M Brengle
S Vickery
65 6 [10] M Brengle
S Vickery
6 6
WC A Zamarripa
M Zamarripa
77 2 [5] M Brengle
S Vickery
6 7
  S Marand
T Moore
4 1 2 Y-c Hsieh
X You
0 5
2 Y-c Hsieh
X You
6 6

References

  1. "W60 Berkeley". www.itftennis.com.
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