2018 Boyd Tinsley Clay Court Classic – Doubles

Jovana Jakšić and Catalina Pella were the defending champions, but decided not to participate.

Doubles
2018 Boyd Tinsley Clay Court Classic
Champions Sophie Chang
Alexandra Mueller
Runners-up Ashley Kratzer
Whitney Osuigwe
Final score3–6, 6–4, [10–7]

Sophie Chang and Alexandra Mueller won the title after defeating Ashley Kratzer and Whitney Osuigwe 3–6, 6–4, [10–7] in the final.

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 I Bara
M Duque Mariño
6 6
  K Cartwright
K Pierre-Louis
3 1 1 I Bara
M Duque Mariño
2 7 [10]
WC A Smith
N Subhash
6 6 WC A Smith
N Subhash
6 5 [5]
  M Mateas
R Yurovsky
2 4 1 I Bara
M Duque Mariño
6 4 [4]
3 S Chang
A Mueller
6 6 3 S Chang
A Mueller
1 6 [10]
  L Chirico
F Di Lorenzo
3 3 3 S Chang
A Mueller
7 6
  P Januskova
R Ozaki
4 6 [7] C Rosatello
AS Sánchez
5 2
  C Rosatello
AS Sánchez
6 3 [10] 3 S Chang
A Mueller
3 6 [10]
  V Duval
J Loeb
6 4 [10] A Kratzer
W Osuigwe
6 4 [7]
  Q Gleason
A Weinhold
2 6 [8] V Duval
J Loeb
6 62 [10]
  A Kratzer
W Osuigwe
6 6 A Kratzer
W Osuigwe
3 77 [12]
4 PC Gonçalves
S Marand
3 4 A Kratzer
W Osuigwe
6 2 [12]
  J Cristian
K Day
1 3 I Neel
M Sanchez
4 6 [10]
  I Neel
M Sanchez
6 6 I Neel
M Sanchez
6 1 [20]
  R McAdoo
K Stewart
6 4 [7] 2 A Guarachi
E Routliffe
2 6 [18]
2 A Guarachi
E Routliffe
2 6 [10]

References

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