1990 Calder Cup playoffs

The 1990 Calder Cup playoffs of the American Hockey League began on April 4, 1990.[1] The eight teams that qualified, four from each division, played best-of-seven series for Division Semifinals and Division Finals. The division champions played a best-of-seven series for the Calder Cup. The Calder Cup Final ended on May 18, 1990, with the Springfield Indians defeating the Rochester Americans four games to two to win the Calder Cup for the sixth time in team history.[2] Despite an injury preventing him from playing in the final game, Springfield goaltender Jeff Hackett won the Jack A. Butterfield Trophy as the MVP of the playoffs.[3]

1990 Calder Cup playoffs
Tournament details
DatesApril 4-May 18, 1990
Teams8
Final positions
ChampionsSpringfield Indians
Runner-upRochester Americans
← 1989
1991 →

The league instituted trophies for division champions in the playoffs; the Richard F. Canning Trophy in the North Division, and the Robert W. Clarke Trophy in the South Division.[4][5]

Playoff seeds

After the 1989-90 AHL regular season, the top four teams from each division qualified for the playoffs. The Sherbrooke Canadiens finished the regular season with the best overall record for the second straight season.[6]

Northern Division
  1. Sherbrooke Canadiens - 102 points
  2. Cape Breton Oilers - 85 points
  3. Springfield Indians - 80 points
  4. Halifax Citadels - 80 points

Southern Division
  1. Rochester Americans - 95 points
  2. Adirondack Red Wings - 95 points
  3. Baltimore Skipjacks - 93 points
  4. Utica Devils - 92 points

Bracket
Division Semifinals Division Finals Calder Cup Final
         
1 Sherbrooke 4
4 Halifax 2
1 Sherbrooke 2
Northern Division
3 Springfield 4
2 Cape Breton 2
3 Springfield 4
N3 Springfield 4
S1 Rochester 2
1 Rochester 4
4 Utica 1
1 Rochester 4
Southern Division
3 Baltimore 2
2 Adirondack 2
3 Baltimore 4

In each round, the team that earned more points during the regular season receives home ice advantage, meaning they receive the "extra" game on home-ice if the series reaches the maximum number of games. There is no set series format due to arena scheduling conflicts and travel considerations.[7]

Division Semifinals
Note: Home team is listed first.

(1) Sherbrooke Canadiens vs. (4) Halifax Citadels
Sherbrooke won series 4 – 2

(2) Cape Breton Oilers vs. (3) Springfield Indians
Springfield won series 4 - 2

(1) Rochester Americans vs. (4) Utica Devils
Rochester won series 4 - 1

(2) Adirondack Red Wings vs. (3) Baltimore Skipjacks
Baltimore won series 4 - 2

Division Finals

(1) Sherbrooke Canadiens vs. (3) Springfield Indians
Springfield won series 4 - 2

(1) Rochester Americans vs. (3) Baltimore Skipjacks
Rochester won series 4 - 2

Calder Cup Final

(S1) Rochester Americans vs. (N3) Springfield Indians
Springfield won series 4 - 2

See also

References
  1. 1990 AHL playoff results The Internet Hockey Database. Retrieved on May 5, 2008.
  2. Calder Cup champions Archived 2008-05-26 at the Wayback Machine caldercup.com. Retrieved on May 5, 2008.
  3. Jack A. Butterfield Trophy Archived 2008-09-17 at the Wayback Machine ahlhalloffame.com. Retrieved on May 6, 2008.
  4. Richard F. Canning Trophy Archived 2008-01-20 at the Wayback Machine ahlhalloffame.com. Retrieved on May 6, 2008.
  5. Robert W. Clarke Trophy Archived 2008-01-20 at the Wayback Machine ahlhalloffame.com. Retrieved on May 6, 2008.
  6. 1989-90 AHL standings The Internet Hockey Database. Retrieved on May 5, 2008.
  7. Frequently asked questions Archived 2008-05-09 at the Wayback Machine theahl.com. Retrieved on May 12, 2008.
Preceded by
1989 Calder Cup playoffs		 Calder Cup playoffs
1990		 Succeeded by
1991 Calder Cup playoffs
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