1989 European Competition for Women's Football

The 1989 European Competition for Women's Football took place in West Germany. It was won by the hosts in a final against defending champions Norway. Again, the competition began with four qualifying groups, but this time the top two countries qualified for a home-and-away quarter final, before the four winners entered the semi-finals in the host nation.[1]

1989 European Competition for Women's Football
Fußball-Europameisterschaft der Frauen 1989
Tournament details
Host countryWest Germany
Dates28 June – 2 July
Teams4
Venue(s)3 (in 3 host cities)
Final positions
Champions West Germany (1st title)
Runners-up Norway
Third place Sweden
Tournament statistics
Matches played4
Goals scored13 (3.25 per match)
Top scorer(s) Sissel Grude
Ursula Lohn
(2 goals each)
Best player(s) Doris Fitschen

Qualification

Squads

For a list of all squads that played in the final tournament, see 1989 European Competition for Women's Football squads

Semifinals


Sweden 12 Norway
Videkull  54' Report
NFF Report (in Norwegian)
SvFF Report (in Swedish)
Report
Medalen  1'
Grude  52'
Attendance: 3,000
Referee: Cornelius Bakker (Netherlands)

Third place playoff

Sweden 21 (a.e.t.) Italy
Sundhage  43'
H. Johansson  94'
Report
FIGC Report (in Italian)
SvFF Report (in Swedish)
Report
Ferraguzzi  28'
Attendance: 2,500
Referee: Ivan Gregr (Czechoslovakia)

Final

West Germany 41 Norway
Lohn  22', 36'
Mohr  45'
Fehrmann  73'
Report
DFB Report (in German)
NFF Report (in Norwegian)
Report
Grude  54'

Awards

 1989 European Competition for Women's Football Winners 

West Germany
First title

Goalscorers

2 goals
1 goal

References

  1. "1989: Germany arrive in style –". Uefa.com. Retrieved 23 August 2012.
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